x^2+12x=288

Solution for x^2+12x=288 equation:

x^2+12x=288

We move all terms to the left:

x^2+12x-(288)=0

a = 1; b = 12; c = -288;
Δ = b2-4ac
Δ = 122-4·1·(-288)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-36}{2*1}=\frac{-48}{2}
=-24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+36}{2*1}=\frac{24}{2}
=12
$